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The angle of elevation to a nearby tree from a point on the ground is measured to be 74^{\circ} ∘ . How tall is the tree if the point on the ground is 54 feet from the tree? Round your answer to the nearest tenth of a foot if necessary.

Sagot :

The height of the tree whose angle of elevation is [tex]74^{0}[/tex] and 54 feet tall is 188 foot.

Height of the tree= 188 foot (rounding off nearest tenth)

What is angle of elevation?

The angle of elevation in math is "the angle formed between the horizontal line and the line of sight when an observer looks upwards is known as an angle of elevation".

We know by trigonometric ratios,

[tex]tan \; \theta = \frac{P}{B}[/tex]

[tex]tan \; 74^0 \;[/tex] = [tex]\frac{P}{54}[/tex]

3.48 = [tex]\frac{P}{54}[/tex]

P= 3.48 x 54

 = 187.92 feet

 ≈ 188 foot (rounding off nearest tenth)

The height of the tree whose angle of elevation is  and 54 feet tall is 188 foot.

Learn more about angle of elevation here:

https://brainly.com/question/21137209

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