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Sagot :
Answer:
7 millicuries
Step-by-step explanation:
A period of 10 days is 2 times the half-life of 5 days.
In the first 5 days, the amount of the chemical decayed by half from 28 millicuries to 14 millicuries. In the next 5 days, it decayed by half again, from 14 millicuries to 7 millicuries.
10 days later, 7 millicuries of the chemical remains.
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