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Consider the division of 8y2 – 12y + 4 by 4y.





What are the values of a and b?

a = 2y and b = 3
a = and b = –3y
a = 2y and b = –3
a = and b = 3y

Sagot :

Notice that the dividend [tex]8y^2-12y+4[/tex] has tree terms with [tex]a=8y^2[/tex], [tex]b=-12y[/tex], c [tex]c=4[/tex]

Now, to divided our dividend [tex]8y^2-12y+4[/tex] by the monomial (single term) [tex]4y[/tex], the easiest thing to do is divide each term of the dividend by the monomial:

[tex]8y^2-12y+4[/tex] ÷ [tex]4y[/tex] = [tex]\frac{8y^2-12y+4}{4y}=\frac{8y^2}{4y}-\frac{12y}{4y}+\frac{4}{4y}=2y-3+\frac{1}{y}[/tex]

After performing the division we get that now [tex]a=2y[/tex] and [tex]b=-3[/tex]

We can conclude that the correct answer is a = 2y and b = –3

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