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An elevator is moving with an acceleration of 2.5 m/s. Find the tension in the cables if the total mass of a man and elevator is 80kg. When;
a) Moving up
b) Moving down​

Sagot :

batolisis

The tension in the cables are :  a) 984 N when moving up,

b) 584 N when movng down

Given data:

mass = 80 kg

Acceleration = 2.5 m/s

Determine the tension in the cables

A) When moving up

Tension in the cable = m*g + m*a

                                  = 80 * 9.8 + 80 * 2.5

                                  =  984 N

B) When moving down

Tension in the cable = m*g - m*a

                                  = 80 * 9.8 - 80 * 2.5

                                  = 584 N

Hence we can conclude that the tension in the cable are 984 N moving up and 584 moving down.

Learn more about tension : https://brainly.com/question/918617

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