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complete the square 2x2- 12x+ 26 = 10

Sagot :

luana
[tex]2x^2-12x+26=10\ \ \ | subtract\ 10\\\\ 2x^2-12x+16=0\ \ \ | divide\ by\ 2\\\\ x^2-6x+8=0\\\\ put\ into\ form:\ (x+d)^2+c=0\\ -6x=2xd\ \ \ | divide\ by\ x\\ d=-3\\ 8=d^2+c\\ 8=9+c\ \ \ | subtract\ 9\\ c=-1\\\\ After\ completing\ the\ square:\\ (x-3)^2-1=0[/tex]
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