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If 130.0 g of steam at 200.0 °C absorbs 900.0 kJ of heat energy, what will be its increase in temperature?

Help pleaseeeeee


If 1300 G Of Steam At 2000 C Absorbs 9000 KJ Of Heat Energy What Will Be Its Increase In Temperature Help Pleaseeeeee class=

Sagot :

Answer:

t=1855.45 C

Explanation:

m=0.13kg t1=200C H=900000J  Cp=4182J/kgC

h=m*cp*change in temperature

900*10^3=0.13*4182*(T-200)

1655.45=t-200

t=1855.45 C