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9
Triangle UVW, with vertices U(3,-6),
V(9,-8), and W(7,-2), is drawn inside a
rectangle, as shown below.
y
2
1
-2
-1
1
2
3
4
5
6
7
8
9
10
-1
W
-2
-3
-4
-5
-6
U
-7
-8
V
-9
-10
What is the area, in square units, of
triangle UVW?

9 Triangle UVW With Vertices U36 V98 And W72 Is Drawn Inside A Rectangle As Shown Below Y 2 1 2 1 1 2 3 4 5 6 7 8 9 10 1 W 2 3 4 5 6 U 7 8 V 9 10 What Is The Ar class=

Sagot :

The Area of Triangle UVW be 16 squared units.

What is Area of Triangle?

The area of a triangle is equal to half the product of its base and height, i.e., A = 1/2 × b × h.

Area of triangle I = [tex]\frac{1}{2} *b*h[/tex]

                            = 0.5  x 4 x 4

                          = 8 units

Area of triangle II= [tex]\frac{1}{2} *b*h[/tex]

                            = 0.5 x 2 x 6

                           = 6 units

Area of triangle III = [tex]\frac{1}{2} *b*h[/tex]

                              = 0.5 x 2 x 6

                              = 6 units

Area of rectangle = length x breadth

                               = 6 x 6

                               = 36units

Area of triangle UVW = Area of rectangle -(Area triangle I + Area of                          

                                      triangle II +Area of triangle III)

                                   = 36 - ( 8 + 6 + 6)

                                   = 36 - 20

                                   = 16 square units

Hence the Area of Triangle UVW = 16 square units.

Learn more about area of triangle here:

https://brainly.com/question/11952845

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