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A 104.5 mL intravenous (IV) solution contains 5.10 g of glucose (C6H12O6). What is the molarity of this solution? The molar mas of glucose is 180.16 g/mol.

Sagot :

Answer:

Molarity=0.271M

Explanation:

molarity=moles/volume

moles=5.10/180.16

=0.0283 moles

volume=0.1045L

Molarity=0.0283/0.1045

             =0.271M

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