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A radioactive compound with mass 470 grams decays at a rate of 3% per hour. Which
equation represents how many grams of the compound will remain after 6 hours?
Submit Answer
O C = 470(0.03)
O C = 470(0.7)
O C = 470(1 + 0.03)
C = 470(1 – 0.03)

Sagot :

After 6 hours the radioactive compound with mass 470 grams becomes 391.49 grams and the equation will be C is equal to 470(1-0.03)^6.

What is exponential decay?

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

We know the decay can be as:

[tex]\rm C = a(1-r)^t[/tex]

We have:

a = 470 grams

r = 3% = 0.03

t = 6 hours

[tex]\rm C = 470(1-0.03)^6[/tex]

C = 391.49 grams

Thus, after 6 hours the radioactive compound with mass 470 grams becomes 391.49 grams and the equation will be C is equal to 470(1-0.03)^6.

Learn more about the exponential decay here:

brainly.com/question/14355665

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