Answered

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A 4.3 L gas bubble at STP is heated to 984 K, and the pressure increases to 1520 mmHg. What is the new volume?

Sagot :

Answer:

v2=40.35L

Explanation:

p1v1/t1=p2v2/t2

v2=t2p1v1/t1p2

v2=984*760*22.4/273.15*1520

v2=40.35 L

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