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Sagot :
The concentration of KBr in the resultion solution is 0.34 M
Stoichiometry
From the question, we are to determine the concentration of KBr in the resulting solution
First, we will determine the number of mole of KBr present
Using the formula,
[tex]Number\ of\ moles = \frac{Mass}{molar\ mass}[/tex]
Mass of KBr = 20.1 g
Molar mass of KBr = 119.00 g/mol
∴ Number of moles of KBr present = [tex]\frac{20.1}{119.00}[/tex]
Number of moles of KBr present = 0.1689 mole
Now, for the concentration of the KBr
Using the formula,
[tex]Concentration = \frac{Number\ of\ moles}{Volume}[/tex]
Volume of solution = 500.0 mL = 0.50 L
∴ Concentration of KBr = [tex]\frac{0.1689}{0.50}[/tex]
Concentration of KBr = 0.3378 M
Concentration of KBr ≅ 0.34 M
Hence, the concentration of KBr in the resultion solution is 0.34 M
Learn more on Stoichiometry here: https://brainly.com/question/17619783
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