dgsteele06oxmffr
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Can someone help me with this?

Can Someone Help Me With This class=

Sagot :

Hrishii

Answer:

[tex]\huge\purple{ x^2 +(y+2)^2 = 4}[/tex]

Step-by-step explanation:

Circle is centred at (0, -2)

-> h = 0 & k = - 2

radius of the circle (r) = y-coordinate of the center = - 2

Equation of circle in standard form is given as:

[tex](x-h)^2 +(y-k)^2 = r^2[/tex]

Plugging the values of h, k and r in the above equation, we find:

[tex](x-0)^2 +[y-(-2)]^2 = (-2)^2[/tex]

[tex]\implies\huge\orange{ x^2 +(y+2)^2 = 4}[/tex]

This is the required equation of circle.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.