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Sagot :
The concentration of the new solution of the ammonium sulphate, (NH₄)₂SO₄ given the data is 0.4 M
How to determine the mole of (NH₄)₂SO₄
- Mass of (NH₄)₂SO₄ = 66.05 g
- Molar mass of (NH₄)₂SO₄ = 132.1 g/mol
- Mole of (NH₄)₂SO₄ =?
Mole = mass / molar mass
Mole of (NH₄)₂SO₄ = 66.05 / 132.1
Mole of (NH₄)₂SO₄ = 0.5 mole
How to determine the molarity of (NH₄)₂SO₄
- Mole of (NH₄)₂SO₄ = 0.5 mole
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity of (NH₄)₂SO₄ =?
Molarity = mole / Volume
Molarity of (NH₄)₂SO₄ = 0.5 / 0.25
Molarity of (NH₄)₂SO₄ = 2 M
How to determine the molarity of the diluted solution
- Volume of stock solution (V₁) = 10 mL
- Molarity of stock solution (M₁) = 2 M
- Volume of diluted solution (V₂) = 50 mL
- Molarity of diluted solution (M₂) =?
M₁V₁ = M₂V₂
2 × 10 = M₂ × 50
20 = V₂ × 50
Divide both side by 50
M₂ = 20 / 50
M₂ = 0.4 M
Learn more about dilution:
https://brainly.com/question/15022582
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