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If y varies jointly with x and z, and y = 200 when x = 8 and z = 10, what is x when y = 165 and z = 11? what is the value of k? 250 160 5.2 2.5

Sagot :

The value of x is 6 and the value of k is 2.5. The correct option is the last option - 2.5

Variation

From the question, we are to determine the value of k, that is, the constant of proportionality

From the given information,

y varies jointly with x and z

Mathematically, this can be written as

y ∝ xz

Then, introducing the constant of proportionality, k, we get

y = kxz

Also, from the given information

y = 200 when x = 8 and z = 10

Putting these values into the equation, we get

200 = k × 8 × 10

200 = 80k

∴ k = 200/80

k = 2.5

Now, for the value of x when y = 165 and z = 11

Using the equation

y = kxz

Then, put the parameters into the equation

165 = 2.5 × x × 11

165 = 27.5x

∴ x = 165 / 27.5

x = 6

Hence, the value of x is 6 and the value of k is 2.5. The correct option is the last option - 2.5

Learn more on Variation here: https://brainly.com/question/4598828

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antonia51

Answer: 2.5

Step-by-step explanation: I did the quiz

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