Answered

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Two students created a game of dice. they determined that each roll would add the value of the die if it was an odd number. if the roll was even, it would subtract the value of the die. (for example, a roll of 2 would subtract two points, but a roll of 3 would add three points.) what is the expected value for this game? –3 –0.5 0 0.5

Sagot :

facundo3141592

The expected value for the given experiment is:

E = -0.5

How to get the expected value?

For an experiment with the possible events {x₁, x₂, ..., xₙ}, each with the correspondent probability {p₁, p₂, ..., pₙ}, the expected value is defined as:

E = x₁*p₁ + ... + xₙ*pₙ

In this case, all the probabilities are equal to 1/6 (assuming that the dice is fair), then we have:

E = (1/6)*(1 - 2 + 3 - 4 + 5 - 6) = (1/6)*(-3) = -0.5

We conclude that the expected value for the experiment is -0.5

If you want to learn more about expected values:

https://brainly.com/question/15858152

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quint1836

Answer:

B

Step-by-step explanation:

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