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Four different constant forces are exerted on a 2. 0 kg object. The figure represents the magnitude and direction of each force. If the object is initially at rest, how long will it take the object to reach a speed of 2. 0 m/s?.

Sagot :

Based on the mass of the object, and its acceleration, the time taken to reach a speed of 2.0 m/s is 4 seconds.

How many seconds will the object take to reach the required speed?

The time can be found as:

= Required speed / Acceletation

Accelaration is:

= Force / Mass

= (0.99iN + 0jN) / 2kg

= 0.5 ms⁻²

Time taken is:

= 2 / 0.5

= 4 seconds

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Since the force that axts on the object  is the resultant force, the time taken is 0.8 s.

What is resolution of forces?

Since force is a vector, it can be resolved into its components. From the complete question, the componenets of the force are;

Vertical component;

  • 5N sin 37
  • 3N sin 90
  • 17 N
  • -20N
  • Total = 3 + 3 + 17 - 20 = 3 N

Horizontal component;

  • 5N cos 37
  • 3N cos 90
  • Total = 3.99 + 0 = 4

Resultant force = √(3)^2 + (4)^2 = 5N

Now;

F = ma

a = F/m

a = 5N/2. 0 kg

a = 2.5 m/s^2

Given that;

v = u + at

since u = 0 (object started from rest)

2 = 2.5 * t

t = 2/2.5 = 0.8 s

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