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Find the value of x to 2dp in the equation 2x² + 5x = 9​

Sagot :

bediluhailu

Answer:

where x1=-3.71 and x2=1.21

Step-by-step explanation:

first= 2x+5x-9=0, a=2,b=5,c=-9, x=

[tex] \sqrt{ {5 }^{2} } - 4 \times 2( - 9) \: over4[/tex]

second x=

[tex] \sqrt[ - 5 + ]{25 + 72} over4[/tex]

x=

[tex] \sqrt[ - 5 +4 ]{97} [/tex]

[tex] \sqrt[ - 5 - 4]{97} [/tex]

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