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Water flows into a vertical cylindrical tank at the rate of 24 cubic ft per minute. If the radius of the tank is 4 ft, how fast is the surface rising?​

Sagot :

given:

per min= 24 cubic ft

radius= 4 ft

to find:

how fast the surface rises.

solution:

[tex]area = \pi {r}^{2} [/tex]

[tex]a = \pi \times {4}^{2} [/tex]

[tex]a = 50.24 \: {ft}^{2} [/tex]

[tex]v = 24 \: {ft}^{3} [/tex]

[tex] = \frac{24}{50.24} [/tex]

[tex] = 0.48[/tex]

therefore, the rising in the surface area is 0.48 feet per minute.

nabeemmm

24 / 50.24 = 0.48 feet per minute

so the answer to your question is 0.48 feet per minute.

hope this helps you

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