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Suppose that the potential energy of a particle constrained

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The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

Slope of the graph

The slope of the graph when the potential energy of a particle constrained in on x-axis is determined as follows;

F = -dU/dx

-dU = Fdx

dU = -Fdx

U = -∫(kx + ax³)dx

U = kx²/2 - ax⁴/4

When, x = 0, U = 0

When U = 0;

[tex]x = \pm \sqrt{\frac{2k}{a} }[/tex]

The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.

Complete question is below:

Suppose that the potential energy of a particle constrainedon x-axis and subjected to a force in the same direction, at a fuction of F(x) = -kx + ax³.

Find the functional form of the potential energy.

Learn more about potential energy here: https://brainly.com/question/1242059

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