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Sagot :
The position and nature of the image are magnified,
What is the focal length?
Focal length, usually represented in millimeters (mm), is the basic description of a photographic lens.
Radius of curvature of the mirror, R = -60 cm
Focal length of the mirror, f = -30 cm
Object distance, u = -20 cm
Let v is the position of the mirror. It can be calculated as :
[tex]\rm \dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{-30}-\dfrac{1}{-20}\\\\\\\dfrac{1}{v}=\dfrac{-20 - (-30)}{(-30)(-20)}\\\\\dfrac{1}{v}=\dfrac{10}{(-30)(-20)}\\\\\dfrac{1}{v}=\dfrac{10}{600}\\\\\dfrac{1}{v}=\dfrac{1}{60}\\\\v=60[/tex]
The image is formed at a distance of 60 cm behind the concave mirror.
[tex]\rm m=\dfrac{-v}{u}\\\\m=\dfrac{-60}{-30}\\\\m=2[/tex]
The image is magnified.
Hence, the position and nature of the image are magnified,
Learn more about focal length here;
https://brainly.in/question/7222487
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