Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A proton of energy 900gev collides with a stationary proton. Find the available energy ea. The rest energy of the proton is 938mev

Sagot :

onyebuchinnaji

The total energy available during the collision of the two protons is determined as 900,938 MeV.

Total energy available during the collision

Based on the principle of conservation of energy, the total energy of the two protons during the collision will be conserved.

Available energy = Er + K

Where;

  • Er is the rest energy
  • K is the kinetic energy

Available energy = 938 MeV + 900 GeV

Available energy = 938 Mev + 900 x 10³ MeV

Available energy = 938 MeV + 900,000 MeV

Available energy = 900,938 MeV

Learn more about rest energy here: https://brainly.com/question/15047418

#SPJ1

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.