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Construct a confidence interval of the population proportion at the given level of confidence. X=540

Sagot :

The lower bound of the confidence interval is 0.55.

What is the confidence interval of the population proportion?

A confidence interval for a proportion is a range of values that is likely to contain a population proportion with a certain level of confidence.

Construct a confidence interval of the population proportion at the given level of confidence x equals = 540, n equals = 900, 96% confidence.

The value of p is;

[tex]\rm p=\dfrac{x}{n}\\\\p =\dfrac{540}{900}\\\\p=0.6[/tex]

The standard error of the proportion is:

[tex]\rm \sigma_p=\sqrt{\dfrac{p(1-p)}{n}} \\\\ \sigma_p=\sqrt{\dfrac{0.6(1-0.6)}{540}} \\\\ \sigma_p=\sqrt{\dfrac{0.6\times 0.4}{540}} \\\\ \sigma_p=\sqrt{\dfrac{0.24}{540}} \\\\ \sigma_p=\sqrt{0.00044}\\\\ \sigma_p=0.02[/tex]

The critical z-value for a 94% confidence interval is z = 2.04

The margin of error (MOE) can be calculated as:

[tex]\rm Margin \ of \ error=\sigma_p \times z =2.04 \times0.02 =0.04[/tex]

Then, the lower bound of the confidence interval is;

[tex]Lower \ bound =p-x\times \sigma_p=0.6-0.04=0.55[/tex]

Hence, the lower bound of the confidence interval is 0.55.

Learn more about confidence intervals here;

https://brainly.com/question/17042789

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