Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The molar concentration of Cl⁻ ions in a 1. 00 m solution of AgCl₂ with no excess silver ions is 0.020M.
How do we determine the molar concentration?
Molar concentration of Chloride ions present in the silver chloride solution will be calculated by using the formation constant equation as:
Kf = [AgCl₂] / [Ag²⁺][Cl⁻]²
For AgCl₂ value of Kf is 2.5×10⁵.
Chemical reaction with ICE table is:
Ag²⁺(aq) + 2Cl⁻(aq) → AgCl₂
Initial: 0 0 1
Change: +x +2x -x
Equilibrium: x 2x 1-x
On putting all the values on the Kf equation, we get
2.5×10⁵ = (1-x) / (x)(2x)²
x is negligible as compared to 1 so the term 1-x becomes 1,
2.5×10⁵ = 1 / 4x³
x = 9.97 × 10⁻³ M
Concentration of chloride ions = 2x = 2(9.97 × 10⁻³) = 0.020M.
Hence the molar concentration of chloride ions is 0.020M.
To know more about molar concentration, visit the below link:
https://brainly.com/question/21841645
#SPJ4
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.