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Sagot :
The entropy change if one mole of water is warmed from 0 degree C to 100 degree C is 1,316.7 J/K.
How do we calculate the entropy change?
Change in entropy will be measured by using the below equation as:
ΔS = (n)(Cp)ln(T₂/T₁), where
n = moles of water = 1 mol
Cp = specific heat of water = 4180 J/mol.K
T₂/T₁ = ratio of temperatures in K = 373 / 273 = 1.37 K
On putting values, we get
ΔS = (1)(4180)ln(1.37) = (4180)(0.315)
ΔS = 1,316.7 J/K
Hence required value of entropy is 1,316.7 J/K.
To know more about entropy, visit the below link:
https://brainly.com/question/419265
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