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What is the entropy change if one mol of water is warmed from 0 c to 100 c

Sagot :

The entropy change if one mole of water is warmed from 0 degree C to 100 degree C is 1,316.7 J/K.

How do we calculate the entropy change?

Change in entropy will be measured by using the below equation as:

ΔS = (n)(Cp)ln(T₂/T₁), where

n = moles of water = 1 mol

Cp = specific heat of water = 4180 J/mol.K

T₂/T₁ = ratio of temperatures in K = 373 / 273 = 1.37 K

On putting values, we get

ΔS = (1)(4180)ln(1.37) = (4180)(0.315)

ΔS = 1,316.7 J/K

Hence required value of entropy is 1,316.7 J/K.

To know more about entropy, visit the below link:

https://brainly.com/question/419265

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