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Sagot :
The value of change in kinetic energy, when fish with mass 0. 65 kg is leaping to the right at 15 m/s, is 93.1 J.
What is kinetic energy?
Kinetic energy is a type of energy, which a body is posses due to its motion. The kinetic energy of a body can be found with the following formula,
[tex]KE=\dfrac{1}{2}mv^2[/tex]
Here, (m) is the mass of the body, and (v) is the speed of the body.
When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v[/tex]
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1,2) are used for fish 1 and 2.
The mass of the first fish is 0. 65 kg. This fish leaping to the right at 15.0 m/s collides inelastically with another fish with mass 0.950 kg leaping to the left at 13.5 m/s. Put the values,
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v\\0.65\times15 +0.95\times(-13.5) = (0.65 + 0.95)\times v[/tex]
The value of initial velocity of the second fish is taken negative as it is leaping to the left.
[tex]0.65\times15 +0.95\times(-13.5) = (0.65 + 0.95)\times v\\v=-\dfrac{3.075}{1.6}\\v=-1.9219\rm\; m/s[/tex]
This is the final velocity. Now to find the change in kinetic energy use the formula of kinetic energy,
[tex]\Delta KE=\dfrac{1}{2}(0.65)(12-(-1.9219))^2\\\Delta KE=93.1\rm\; J[/tex]
Thus, the value of change in kinetic energy, when fish with mass 0. 65 kg is leaping to the right at 15 m/s, is 93.1 J.
Learn more about the kinetic energy here;
https://brainly.com/question/25959744
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