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Sagot :
Final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
What is conservation of momentum?
Momentum of an object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity. By the law of conservation of momentum,
[tex]m_1u_1 + m_2u_2 = (m_1+m_2)v[/tex]
Here, (m) is the mass, (u) is initial velocity before collision, v is final velocity after collision and (subscript 1, and 2) are used for body 1 and 2 respectively. Rewrite the formula for final velocity as,
[tex]v=\dfrac{m_1u_1 + m_2u_2}{(m_1+m_2)}[/tex]
A 0. 060-kg tennis ball, moving with a speed of 5. 82 m/s, has a head-on collision with a 0. 090-kg ball, initially moving in the same direction at a speed of 3.44 m/s. Thus, the initial velocity of the second ball is,
[tex]v_{2f}=5.82+3.44+v_{1f}\\v_{2f}=2.38+v_{1f}[/tex]
Let v1f is the final velocity of first ball. Thus, the initial velocity of the first ball is,
[tex]v_{1f}=\dfrac{(0.060)(5.82) + (0.090)(3.44-2.38)}{(0.060)+(0.090)}\\v_{1f}=2.964\rm\; m/s[/tex]
Thus, final speed of the tennis ball, moving with a speed of 5. 82 m/s , has a head-on collision with a 0. 090-kg ball is 2.964 m/s.
Learn more about the conservation of momentum here;
https://brainly.com/question/7538238
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