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In an isosceles triangle the length of the base is 10 cm

Sagot :

shubhamchouhanvrVT

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

How to calculate the radius?

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

[tex]S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18[/tex]

The radius will be:

 [tex]=\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}[/tex]

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

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