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The load across a 12-v battery consists of a series combination of three resistances are 15 ω, 21 ω, and 24 ω, respectively

Sagot :

The magnitude of the circuit current is 0.20 A. The value of the current in the circuit is found with the help of the ohm's law.

What is ohm’s law?

Ohm's law claims that the voltage across a conductor is directly proportional to the current flowing through it.

All the resistance combined in the series so that the equivalent resistance is;

[tex]\rm R_{eq}= R_1+R_2+R_3 \\\\ R_{eq}=15+21+24 \\\\ R_{eq}=60 \ ohm[/tex]

This current-voltage connection may be expressed mathematically by the Ohm's Law;

V=IR

[tex]\rm I_{total} = \frac{V}{R_{total}} \\\\ \rm I_{total} = \frac{12}{60} \\\\ I_{total} = 0.20 \ A[/tex]

Hence, the magnitude of the circuit current is 0.20 A.

To learn more of the ohm's law, refer to the link;

https://brainly.com/question/796939

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