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What is the magnitude of the force on a 0. 0150 kg particle placed at p? slader

Sagot :

The magnitude of the force on a 0. 0150 kg particle placed at p will be -8 N. Force is defined as the product of mass and acceleration. Its unit is Newton.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The velocity is found as;

[tex]\rm v= \frac{dx}{dt}\\\ v= \frac{d}{dt} (13.00+2.00t+4.00 t^2-3.00t^3)\\\\ v= 2+ 8t -9t^2[/tex]

The acceleration is found as;

[tex]\rm a = \frac{dv}{dt} \\\\ a= \frac{d}{dt} (2-8t-9t^2)\\\\ a = \frac{d}{dt} 98t-9t^2)\\\\\ a=8-18t\\\\ a=8-(18 \times 3.4)\\\\a=-53.2 m/sec^2[/tex]

The value of the force for the given mass is;

[tex]\rm F= maas \times acceleration \\\\ F = m\times a\\\\ F= 0.150 \times (-53.2) \\\\ F= -7.98 \ N\\\\ F= -8\ N[/tex]

Hence, the value of the force is -8 N .

To learn more about the force, refer to the link;

https://brainly.com/question/26115859

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