Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Suppose that x has the density function f(x) = cx 0 < x < 2 identify c

Sagot :

shubhamchouhanvrVT

The value of C=1/3 for the probability density function f(x)=cx , 0<x<2.

What is probability density function?

The probability density function is a function of a continuous random variable, whose integral across an interval gives the probability that the value of the variable lies within the same interval.

Given that:

[tex]f(x)=cx\ \ at\ 0 < x < 2[/tex]

Here we can see that the value of x is varies as 0,1,2

So at 0,1,2 the value of the function is

[tex]f(1)=c\times 1=c\\\\\\f(2)=c\times 2=2c\\\\[/tex]

So the probability density function is given as:

[tex]\sum f(x)=f(1)+F(2)=1\\\\\sum f(x)=c+2c=1[/tex]

[tex]3c=1\\\\c=\dfrac{1}{3}[/tex]

Hence the value of C=1/3 for the probability density function f(x)=cx , 0<x<2.

To know more about probability density function follow

https://brainly.com/question/14214648

#SPJ4

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.