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A gas has an initial volume of 5. 35l. What is the final volume if 588j of work is done on the gas by a constant external pressure of 2. 00atm?

Sagot :

Work done is the exchange of heat from the system and the surrounding. The final volume of the gas in the system is 2.45 L.

What is work done?

Work done is the product of the pressure and the change in the volume of the gas in the system. The formula for work done is given as,

[tex]\rm w = -P\Delta V[/tex]

Given,

Initial volume = 5.35 L

Work done = 588 J

Pressure = 2.00 atm

Work done in joules is converted to L atm as, 588 joules = 5.80 Litres-atmosphere

Substituting values in the above equation:

[tex]\begin{aligned}\rm w &=\rm -P(V_{f} - V_{i})\\\\5.80 &= \rm - 2 (V_{f} - 5.35))\\\\5.80 - 10.7 &= \rm -2V\\\\&= 2.45\;\rm L\end{aligned}[/tex]

Therefore, 2.45 L is the initial volume of the gas.

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