Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A gas has an initial volume of 5. 35l. What is the final volume if 588j of work is done on the gas by a constant external pressure of 2. 00atm?

Sagot :

Work done is the exchange of heat from the system and the surrounding. The final volume of the gas in the system is 2.45 L.

What is work done?

Work done is the product of the pressure and the change in the volume of the gas in the system. The formula for work done is given as,

[tex]\rm w = -P\Delta V[/tex]

Given,

Initial volume = 5.35 L

Work done = 588 J

Pressure = 2.00 atm

Work done in joules is converted to L atm as, 588 joules = 5.80 Litres-atmosphere

Substituting values in the above equation:

[tex]\begin{aligned}\rm w &=\rm -P(V_{f} - V_{i})\\\\5.80 &= \rm - 2 (V_{f} - 5.35))\\\\5.80 - 10.7 &= \rm -2V\\\\&= 2.45\;\rm L\end{aligned}[/tex]

Therefore, 2.45 L is the initial volume of the gas.

Learn more about work done here:

https://brainly.com/question/25086088

#SPJ4

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.