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Sagot :
The area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
What is integration?
It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
We have:
r=6sin(6θ)
First we have to find the limits:
r = 0
6sin(6θ) = 0
θ = nπ/6
n = 0 to n = 1
θ = 0 to θ = π/6
[tex]\rm Area = \int\limits^{\dfrac{\pi}{6}}_0 {6sin6\theta} \, d\theta[/tex]
After calculating the above definite integral, we will get:
Area = 3π/2
Thus, the area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
Learn more about integration here:
brainly.com/question/18125359
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