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The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm

Sagot :

The acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.

What is center of mass?

The center of mass of a object or for a system of object is the point, where the center of distribution of mass in space. The center of mass for the two bodies can be given as,

It can be given as,

[tex]x_{cm}=\dfrac{m_1x_1+m_2x_2}{m_1+m_2}[/tex]

Here, (m) represents the mass and (x) represents the distance.

The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm has to be find out.

The image of the blocks-string-pulley system is attached below. The acceleration of this system is,

[tex]\vec a_{cm}=\left(\dfrac{m_1-m_2}{m_1+m_2}\right)g[/tex]

Thus, the acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.

Learn more about the center of mass here;

https://brainly.com/question/13499822

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