Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
What is center of mass?
The center of mass of a object or for a system of object is the point, where the center of distribution of mass in space. The center of mass for the two bodies can be given as,
It can be given as,
[tex]x_{cm}=\dfrac{m_1x_1+m_2x_2}{m_1+m_2}[/tex]
Here, (m) represents the mass and (x) represents the distance.
The acceleration of the center of mass of the blocks-string-pulley system has magnitude of a_cm has to be find out.
The image of the blocks-string-pulley system is attached below. The acceleration of this system is,
[tex]\vec a_{cm}=\left(\dfrac{m_1-m_2}{m_1+m_2}\right)g[/tex]
Thus, the acceleration of the center of mass of the blocks-string-pulley system has magnitude equal to the ratio of difference to the sum of masses of block multiplied with gravitational acceleration.
Learn more about the center of mass here;
https://brainly.com/question/13499822
#SPJ4

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.