Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
The available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
How to find the available energy after the collision?
The available energy can be found out with the following formula.
[tex]E_a=\sqrt{2E_tE_k++(m_1c^2)^2+(m_2c^2)^2}[/tex]
Here C is the speed of light (3×10⁸ m/s), Et is the energy of proton, Ek is the rest energy.
A proton and an antiproton have equal energies of 450gev. The particles collide head-on. The rest energy of the proton is 938mev
Thus, put the given values in the above formula,
[tex]E_a=\sqrt{2(450\times\dfrac{10^9eV}{1MeV})(938\times\dfrac{10^6eV}{1MeV})+(938\times\dfrac{10^6eV}{1MeV})^2+(938\times\dfrac{10^6eV}{1MeV})}\\E_a=29\rm\; Gev[/tex]
Thus, the available energy ea when the proton and the antiproton have equal energies of 450gev is 29 GeV.
Learn more about the proton here;
https://brainly.com/question/9427701
#SPJ4
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
