At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
What is the solubility of Copper (II) Oxalate in pure water?
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at https://brainly.com/question/23659342.
#SPJ1
The value of solubility for cuc2o4(s) in pure water when the value of solubility product, Ksp for it is 2.9 ×10⁻⁸, is 1.703 × 10⁻⁴.
What is solubility?
The solubility of a chemical compound or an element is the property or ability of it to be dissolved, specially in water.
The solubility for CuC₂O₄(s) in pure water has to be found out. The solubility product is,
[tex]K_{sp}=2. 9 \times 10^{-8}[/tex]
Let suppose x is the molar solubility of CuC₂O₄(s). From the ICE approach solution,
[tex]K_{sp}=x^2\\2. 9 \times 10^{-8}=x^2\\x=\sqrt{2. 9 \times 10^{-8}}\\x=1.703 \times 10^{-4}\rm\; M[/tex]
Thus, the value of solubility for cuc2o4(s) in pure water when the value of solubility product, Ksp for it is 2.9 ×10⁻⁸, is 1.703 × 10⁻⁴.
Learn more about the solubility here;
https://brainly.com/question/4529762
#SPJ4
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.