Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
The value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
What is resonance frequency?
Resonance frequency is the natural frequency of an particle or object. At this frequency, the object tries to vibrate at higher amplitude. It can be calculated with the following formula:
[tex]f=\dfrac{1}{2\pi LC}[/tex]
Here, L is the induction and C is the capacitance.
Let for an L-R-C circuit, the value of resistance is 400 ohm, induction is 0.380 Haney and capacitance is 1.20×10⁻² μF.
Put the values in above formula,
[tex]f=\dfrac{1}{2\pi(0.380)(1.20\times10^{-8})}\\f=2356.8\rm\; Hz[/tex]
The capacitor can withstand a peak voltage of 670 v. Use the following formula to find the value of current as,
[tex]I=2\pi fC\times Vc\\I=2\pi (2356.8)(1.20\times10^{-8})\times 670\\I=0.119\rm\; A[/tex]
The value of resistance is 400 ohms. Thus, the voltage is,
[tex]V=IR\\V=(0.119)(400)\\V=47.6\rm\; V[/tex]
Thus, the value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
Learn more about the resonance frequency here:
https://brainly.com/question/3292140
#SPJ4
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
