Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
What is resonance frequency?
Resonance frequency is the natural frequency of an particle or object. At this frequency, the object tries to vibrate at higher amplitude. It can be calculated with the following formula:
[tex]f=\dfrac{1}{2\pi LC}[/tex]
Here, L is the induction and C is the capacitance.
Let for an L-R-C circuit, the value of resistance is 400 ohm, induction is 0.380 Haney and capacitance is 1.20×10⁻² μF.
Put the values in above formula,
[tex]f=\dfrac{1}{2\pi(0.380)(1.20\times10^{-8})}\\f=2356.8\rm\; Hz[/tex]
The capacitor can withstand a peak voltage of 670 v. Use the following formula to find the value of current as,
[tex]I=2\pi fC\times Vc\\I=2\pi (2356.8)(1.20\times10^{-8})\times 670\\I=0.119\rm\; A[/tex]
The value of resistance is 400 ohms. Thus, the voltage is,
[tex]V=IR\\V=(0.119)(400)\\V=47.6\rm\; V[/tex]
Thus, the value of maximum voltage, when the capacitor can withstand a peak voltage of 670 v is 47.6 volts.
Learn more about the resonance frequency here:
https://brainly.com/question/3292140
#SPJ4
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
