Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The speed of the wave whose wave equation :
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] is 0.20 m/s
speed = 0.20 m/s
What is the speed of wave?
The wave equation is a linear second-order partial differential equation which describes the propagation of oscillations at a fixed speed in some quantity y.
The wave equation is given by:
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] .......................(1)
As we know that the standard form of wave equation is of the form is
On Comparing it with equation (1)
we have,
angular number, k=20
and, angular frequency, ω=4.0 rad/s.
Thus, the speed of the wave is
v=[tex]\frac{\omega}{K}[/tex]
=[tex]\frac{(4.0 rad/s) }{(20 m^{-1}) }[/tex]
=0.20 m/s
The speed of the wave of the wave equation
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] is 0.20 m/s
Learn more above wave equation here:
https://brainly.com/question/10715783
#SPJ4
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
