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The first-order rate constant for the decomposition of n2o5,2n2o5(g)→4no2(g) o2(g)at 70∘c is 6. 82×10−3 s−1. Suppose we start with 2. 60×10−2 mol of n2o5(g) in a volume of 2. 0 l

Sagot :

A decomposition reaction is the breakdown of reactants into two or more products. The concentration of dinitrogen pentoxide after 4 minutes will be 1.63 moles.

What is the first-order rate constant?

The first-order rate constant (k) is the order of the reaction that is the initial rate and is given as 1/s.

The first order is shown as:

[tex]\rm [ln] A = \rm ln [A]_{o} - kt[/tex]

Given,

Initial concentration = 0.013 M

k =  [tex]6.82 \times 10^{-3}\;\rm s^{-1}[/tex]

t = 240 seconds

Substituting values above:

[tex]\begin{aligned} \rm [ln] A &= \rm ln[0.013] - 9 6.82\times 10^{-3} \times 240)\\\\[A] &= \rm e^{ln[0.013]} - (6.82 \times 10^{-3} s^{-1} \times 240 s)\\\\& = 1.6238\end{aligned}[/tex]

Therefore, 1.63 moles will remain after 4 minutes.

Learn more about the first-order reaction here:

https://brainly.com/question/14262919

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