Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The velocity of the ball as it passes a treetop 4. 88 m tall and thrown straight upward with a velocity of 9. 98 m/s is 14 m/s.
What is the equation of motion?
The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.
The third equation of the motion for distance can be given as,
[tex]v^2-u^2=2ah[/tex]
Here, is the u initial body, a is the acceleration of the body and h is the height of it.
The ball is thrown straight upward with a velocity of 9. 98 m/s. The height of it is 4. 88 m. Thus, initial velocity is 4.88 meters and the acceleration due to gravity is 9.98 m/s².
Put the values,
[tex]v^2-u^2=2ah\\v^2-(9.98)^2=2(9.98)(4.88)\\v^2=2(9.98)(4.88)+(9.98)^2\\v\approx 14\rm\; m/s[/tex]
Hence, the velocity of the ball as it passes a treetop 4. 88 m tall and thrown straight upward with a velocity of 9. 98 m/s is 14 m/s.
Learn more about the equation of motion here;
https://brainly.com/question/13763238
#SPJ4
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
