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Sagot :
The molarity of solution which is prepared by dissolving 7. 31 g of Na₂SO₄ in enough water to make 225 ml of solution is 0.22M
How do we calculate molarity?
Molarity of the solution will be calculated by using the below equation as:
M = n/V, where
- V = volume of solution = 225mL = 0.225L
- n is the moles of solute which can be calculated as:
n = W/M, where
- W = given mass of Na₂SO₄ = 7.31g
- M = molar mass of Na₂SO₄ = 142g/mol
n = 7.31/142 = 0.05 mol
On puttig values, we get
M = 0.05 / 0.225 = 0.22M
Hence required molarity is 0.22M.
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