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A solution is prepared by dissolving 7. 31 g of na2so4 in enough water to make 225 ml of solution. Calclate the solutions molarity

Sagot :

The molarity of solution which is prepared by dissolving 7. 31 g of Na₂SO₄ in enough water to make 225 ml of solution is 0.22M

How do we calculate molarity?

Molarity of the solution will be calculated by using the below equation as:

M = n/V, where

  • V = volume of solution = 225mL = 0.225L
  • n is the moles of solute which can be calculated as:

n = W/M, where

  • W = given mass of Na₂SO₄ = 7.31g
  • M = molar mass of Na₂SO₄ = 142g/mol

n = 7.31/142 = 0.05 mol

On puttig values, we get

M = 0.05 / 0.225 = 0.22M

Hence required molarity is 0.22M.

To know more about molarity, visit the below link:

https://brainly.com/question/489225

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