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N inductor has a peak current of 330 μa when the peak voltage at 44 mhz is 2. 8 v

Sagot :

The value of inductance, when N inductor has a peak current of 330 μa when the peak voltage at 44 mhz is 2.8 v, is 8.485×10³ H.

What is inductance?

The inductance is the ability or the property of an electric conductor by which it opposes the amount of current flowing from it. It can be calculated with the following formula.

[tex]X_L=\dfrac{V_{rms}}{I_{rms}}[/tex]

Here, V is voltage and I is current value.

N inductor has a peak current of 330 μa when the peak voltage at 44 mhz is 2.8 v. Put the values in the above formula as,

[tex]X_L=\dfrac{V_{rms}}{I_{rms}}\\X_L=\dfrac{2.8}{330\times10^{-6}}\\X_L=8.485\times10^3 \rm \;H[/tex]

Thus, the value of inductance, when N inductor has a peak current of 330 μa when the peak voltage at 44 mhz is 2.8 v, is 8.485×10³ H.

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