The moles of aluminum sulfate that could be produced from 32.7 grams of aluminum nitrate is 0.07 moles.
What is the relation between mass & moles?
Relation between the mass and moles of any substance will be represented as:
n = W/M, where
W = given mass of aluminum nitrate = 32.7g
M = molar mass of aluminum nitrate = 213 g/mol
Moles of aluminum nitrate = 32.7 / 213 = 0.154 mol
Given chemical reaction is:
3Na₂SO₄(aq) + 2Al(NO₃)₃(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)
From the stoichiometry of the reaction it s clear that,
2 mole of Al(NO₃)₃ = produces 1 mole of Al₂(SO₄)₃
0.154 mole of Al(NO₃)₃ = produces (1/2)(0.154)=0.07 mole of Al₂(SO₄)₃
Hence produced moles of aluminum sulfate is 0.07 moles.
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