At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How many moles of aluminum sulfate, al2(so4)3, could be produced from 32. 7 grams of aluminum nitrate, al(no3)3?

Sagot :

The moles of aluminum sulfate that could be produced from 32.7 grams of aluminum nitrate is 0.07 moles.

What is the relation between mass & moles?

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

W = given mass of aluminum nitrate = 32.7g

M = molar mass of aluminum nitrate = 213 g/mol

Moles of aluminum nitrate = 32.7 / 213 = 0.154 mol

Given chemical reaction is:

3Na₂SO₄(aq) + 2Al(NO₃)₃(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)

From the stoichiometry of the reaction it s clear that,

2 mole of Al(NO₃)₃ = produces 1 mole of Al₂(SO₄)₃

0.154 mole of Al(NO₃)₃ = produces (1/2)(0.154)=0.07 mole of Al₂(SO₄)₃

Hence produced moles of aluminum sulfate is 0.07 moles.

To know more about mass & moles, visit the below link:
https://brainly.com/question/20838755

#SPJ4

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.