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How many moles of aluminum sulfate, al2(so4)3, could be produced from 32. 7 grams of aluminum nitrate, al(no3)3?

Sagot :

The moles of aluminum sulfate that could be produced from 32.7 grams of aluminum nitrate is 0.07 moles.

What is the relation between mass & moles?

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

W = given mass of aluminum nitrate = 32.7g

M = molar mass of aluminum nitrate = 213 g/mol

Moles of aluminum nitrate = 32.7 / 213 = 0.154 mol

Given chemical reaction is:

3Na₂SO₄(aq) + 2Al(NO₃)₃(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)

From the stoichiometry of the reaction it s clear that,

2 mole of Al(NO₃)₃ = produces 1 mole of Al₂(SO₄)₃

0.154 mole of Al(NO₃)₃ = produces (1/2)(0.154)=0.07 mole of Al₂(SO₄)₃

Hence produced moles of aluminum sulfate is 0.07 moles.

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https://brainly.com/question/20838755

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