The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0 is 16/3 or 5.333 square units.
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The region r is enclosed by the curves y₁ = 4 - 4x² and y₂ = 0
The intersection points will be
y₁ = y₂
4 - 4x² = 0
x = ±1
Then the area bounded by the curves will be
[tex]\rm Area = \int _{-1}^1 (y_1- y_2) dx\\\\Area = \int _{-1}^1 (4 - 4x^2) dx\\\\Area = \left [ 4x - \dfrac{4x^3}{3} \right ]_{-1}^1\\\\Area = 4 \left ( 1 + 1 \right ) - \dfrac{4}{3} \left ( 1^3 - (-1)^3 \right )\\\\Area = 8 - \dfrac{8}{3}\\\\Area = \dfrac{16}{3} = 5.333 \[/tex]
More about the area bounded by the curve link is given below.
https://brainly.com/question/24563834
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