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Drawdown at a 0. 20-m diameter well, which has been pumping at a rate of 1,000 m3/day for a long enough time that steady-state conditions have been reached, is determined to be 0. 70 m. The aquifer is 10. 0 m thick. An observation well located 10 m away has been drawn down by 0. 20 m. Determine the hydraulic conductivity of the aquifer

Sagot :

Answer:the aquifer’s hydraulic conductivity  is K = 10.039 m/day

transmissivity T = 331.287 m/day

the drawdown 100 m away from the well is s = 1.452 m

Explanation:Given that :

The  constant pumps rate Q = 2000 m³/day

R₁ =160 m     →    H₁  = 249 m

R₂ = 453 m    →    H₂ = 250 m

The  confined aquifer B is 33 m thick

The hydraulic conductivity K =

K =

K =

K = 10.039 m/day

Transmissivity T = K × B

T = 10.039×33

T = 331.287 m/day

TO find the drawdown 100 m away from the well; we have:

K =

H₃ = 248.548 m

Drawdown (s) = H₂ - H₃

s = (250 -  248.548)m

s = 1.452 m