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Determine the equation of the circle with center (-6, -2 containing the point (-10, -9).

Sagot :

Answer:

x² + 12x + y² + 4y - 25 = 0

Step-by-step explanation:

Equation of a circle

  • (x - h)² + (y - k)² = r²
  • (h, k) = coordinates of circle
  • (x, y) = coordinates of point on circle
  • r = radius

Finding r

  • (-10 + 6)² + (-9 + 2)² = r²
  • r² = 16 + 49
  • r = √65

Making the equation

  • (x + 6)² + (y + 2)² = (√65)²
  • x² + 12x + 36 + y² + 4y + 4 = 65
  • x² + 12x + y² + 4y - 25 = 0
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