Answered

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Write the standard form of the equation of a circle with radius 3 and center (11, 3)

Sagot :

Answer:

x² - 22x + y² - 6y + 121 = 0

Step-by-step explanation:

General Form of Equation

  • (x - h)² + (y - k)² = r²

Solving

  • (x - 11)² + (y - 3)² = (3)²
  • x² - 22x + 121 + y² - 6y + 9 = 9
  • x² - 22x + y² - 6y + 121 = 0
jbooth12

Answer:

(x+11)2+(y−3)2=81

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Step-by-step explanation:

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