Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Write the standard form of the equation of a circle with radius 3 and center (11, 3)

Sagot :

Answer:

x² - 22x + y² - 6y + 121 = 0

Step-by-step explanation:

General Form of Equation

  • (x - h)² + (y - k)² = r²

Solving

  • (x - 11)² + (y - 3)² = (3)²
  • x² - 22x + 121 + y² - 6y + 9 = 9
  • x² - 22x + y² - 6y + 121 = 0
jbooth12

Answer:

(x+11)2+(y−3)2=81

mark me brainliest

Step-by-step explanation:

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.