Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

15 + 21 = 3 (4 + 8)

What is Aida’s error?
Aida used 3 as the factor, which is not common to 15 and 21.
Aida did not correctly divide by the common factor to get (4 + 8).
Aida did not apply the correct operations to the expressions.
Aida wrote two expressions that are not equivalent.

Sagot :

Answer:

Aida did not correctly divide by the common factor to get (4 + 8).

12651241

Answer:

B). Aida did not correctly divide by the common factor to get (4 + 8).

Step-by-step explanation:

Aida applied the distributive property to write the equivalent expressions given as

15 + 21 = 3(4 + 8)

But Aida made a mistake.

Since to get the common factor of 15 and 21 she did not divide these numbers by 3 correctly.

In simple words by division of 3 in 15 and 21, we get 5 and 7 instead of 5 and 8.

Therefore, Aida did not correctly divide by the common factor to get (4 + 8). ⇒ option B is the correct answer.

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.