Answered

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which equation represents a line that passes through (5 1) and has a slope of

Sagot :

The equation of line with point (5,1) and slope ½ is (y-1) = ½ (x-5).

What is the equation of a line?

The equation of a line is given as:

[tex]\rm y=mx+c[/tex]

The equation for the point on slope line is given as:

[tex]\rm (y-y_0)=m(x-x_0)[/tex]

Substituting the given values and the slope:

[tex]\rm (y-1)=\dfrac{1}{2}(x-5)[/tex]

Thus, the equation of line with point (5,1) and slope ½ is (y-1) = ½ (x-5).

Learn more about line equation, here:

https://brainly.com/question/2564656

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