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Sagot :
The equation of line with point (5,1) and slope ½ is (y-1) = ½ (x-5).
What is the equation of a line?
The equation of a line is given as:
[tex]\rm y=mx+c[/tex]
The equation for the point on slope line is given as:
[tex]\rm (y-y_0)=m(x-x_0)[/tex]
Substituting the given values and the slope:
[tex]\rm (y-1)=\dfrac{1}{2}(x-5)[/tex]
Thus, the equation of line with point (5,1) and slope ½ is (y-1) = ½ (x-5).
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