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Help QUICKKKKK please

Help QUICKKKKK Please class=

Sagot :

jcherry99

Answer:

Step-by-step explanation:

Remark

The exposed perimeter of the triangle is just the two smaller legs of the right triangle (6 + 8) + 10 units at the bottom of the rectangle + two 1/2 circles.

The area of the figure is the area of the triangle at the top + the area of the two 1/2 circles + the rectangle in the middle.

Givens

  • Shortest Triangle Leg = 6
  • Middle Triangle Leg = 8
  • Diameter of the 2 half circles
  • pi  = 3.14
  • width of the rectangle in the middle = 8
  • Length of the rectangle = 10
  • d = 8
  • r = d/2 = 8/2 = 4

Formula

A

Perimeter = 2 legs of the triangle + 2 half circles + bottom line

B

Area = (1/2) Leg1*leg2 + pi * r^2 + L * w

Solution

A Perimeter

Perimeter = 6 + 8 + 2*pi *r + 10

Perimeter = 24 + 2*3.14*4

Perimeter = 25.12

B Area

Area = 1/2 * 8 * 6 + 3.14*4^2 + 10* 8

Area = 24 + 50.24+ 80

Area = 150.24

Answer

P = 25.12

Area = 150.24

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