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Two charges of +2.6 μC and –5.4 μC experience an attractive force of 6.5 mN. What is the separation between the charges?

Sagot :

Answer:

Explanation:

[tex]q_{1} =+2.6 X10^{_-6}C \\q_{2} =-5.4 X10^{_-6}C \\F=6.5mN\\F=\frac{Kq_{1}q_{2} }{d^{2} }[/tex]